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4w^2-88w+340=0
a = 4; b = -88; c = +340;
Δ = b2-4ac
Δ = -882-4·4·340
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-48}{2*4}=\frac{40}{8} =5 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+48}{2*4}=\frac{136}{8} =17 $
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